自拍偷拍亚洲综合_国产福利91精品一区_中文字幕在线亚洲三区_一区二区三区四区五区精品

上海交通大學 - 話題

2007 SJTU 計算機復試上機試題(轉載)
查看(3251) 回復(0)
小白楊
  • 積分:482
  • 注冊于:2010-08-02
發表于 2010-11-03 01:02
樓主
Problem A. Old Bill
Input file: standard input
Output file: standard output

Among grandfather's papers a bill was found.
72 turkeys $_679_

The first and the last digits of the number that obviously represented the
total price of those turkeys are replaced here by blanks (denoted _), for
they are faded and are illegible. What are the two faded digits and what
was the price of one turkey?
We want to write a program that solves a general version of the above
problem.
N turkeys $_XYZ_

The total number of turkeys, N, is between 1 and 99, including both. The
total price originally consisted of five digits, but we can see only the
three digits in the middle. We assume that the first digit is nonzero, that
the price of one turkeys is an integer number of dollars, and that all the
turkeys cost the same price.
Given N, X, Y, and Z, write a program that guesses the two faded digits and
the original price. In case that there is more than one candidate for the
original price, the output should be the most expensive one. That is, the
program is to report the two faded digits and the maximum price per turkey
for the turkeys.

Input
The first line of the input file contains an integer N (0<N<100), which
represents the number of turkeys. In the following line, there are the
three decimal digits X, Y, and Z., separated by a space, of the original
price $_XYZ_.

Output
For the input case, there may be more than one candidate for the original
price or there is none. In the latter case your program is to report 0.
Otherwise, if there is more than one candidate for the original price, the
program is to report the two faded digits and the maximum price per turkey
for the turkeys.

Sample input and output
Standard input                         standard output
72                                     3 2 511
6 7 9

5                                      9 5 18475
2 3 7

78                                     0
0 0 5


Problem B. Powerful Calculator
Input file: standard input
Output file: standard output

Today, facing the rapid development of business, SJTU recognizes that more
powerful calculator should be studied, developed and appeared in future
market shortly. SJTU now invites you attending such amazing research and
development work.
In most business applications, the top three useful calculation operators
are Addition (+), Subtraction (-) and Multiplication (×) between two given
integers. Normally, you may think it is just a piece of cake. However,
since some integers for calculation in business application may be very
big, such as the GDP of the whole world, the calculator becomes harder to
develop.
For example, if we have two integers 20 000 000 000 000 000 and 4 000 000
000 000 000, the exact results of addition, subtraction and multiplication
are:
20000000000000000 + 4000000000000000 = 24 000 000 000 000 000
20000000000000000 - 4000000000000000 = 16 000 000 000 000 000
20000000000000000 × 4000000000000000 = 80 000 000 000 000 000 000 000 000
000 000

Note: SJTU prefers the exact format of the results rather than the float
format or scientific remark format. For instance, we need
"24000000000000000" rather than 2.4×10^16.
As a programmer in SJTU, your current task is to develop a program to
obtain the exact results of the addition (a + b), subtraction (a - b) and
multiplication (a × b) between two given integers a and b.

Input
The input file consist of two separate lines where the first line gives the
integer a and the second gives b (|a| <10^200 and |b| < 10^200).

Output
For the input file, output three separate lines showing the exact results
of addition (a + b), subtraction (a - b) and multiplication (a × b) of
that case, one result per lines.

Sample input and output
Standard input                        standard output
20000000000000000                     24000000000000000
4000000000000000                      16000000000000000
                                      80000000000000000000000000000000


Problem C. Sum of Factorials
Input file: standard input
Output file: standard output

John von Neumann, b. Dec. 28, 1903, d. Feb. 8, 1957, was a
Hungarian-American mathematician who made important contributions to the
foundations of mathematics, logic, quantum physics, meteorology, science,
computers, and game theory. He was noted for a phenomenal memory and the
speed with which he absorbed ideas and solved problems. In 1925 he received
a B.S. diploma in chemical engineering from Zurich Institute and in 1926 a
Ph.D. in mathematics from the University of Budapest, His Ph.D.
dissertation on set theory was an important contributions to the subject.
At the age of 20, von Neumann proposed a new definition of ordinal numbers
that was universally adopted. While still in his twenties, he made many
contributions in both pure and applied mathematics that established him as
a mathematician of unusual depth. His Mathematical Foundation of Quantum
Mechanics (1932) built a solid framework for the new scientific discipline.
During this time he also proved the mini-max theorem of GAME THEORY. He
gradually expanded his work in game theory, and with coauthor Oskar
Morgenstern he wrote Theory of Games and Economic Behavior (1944).
There are some numbers which can be expressed by the sum of factorials. For
example 9, 9 = 1! + 2! + 3! . Dr. von Neumann was very interested in such
numbers. So, he gives you a number n, and wants you to tell whether or not
the number can be expressed by the sum of some factorials.
Well, it is just a piece of case. For a given n, you will check if there
are some xi, and let n equal to
∑t (上標) i=1(下標) xi! (t≥1, xi≥0, xi = xj <==> i = j)
      t
即  ∑    xi! (t≥1, xi≥0, xi = xj <==> i = j)
      i=1
If the answer is yes, say "YES"; otherwise, print out
"NO".

Input
You will get a non-negative integer n (n≤1,000,000) from input file.

Output
For the n in the input file, you should print exactly one word ("YES" or
"NO") in a single line. No extra spaces are allowed.

Sample input and output
Standard input                      standard output
9                                   YES
2                                   YES


Problem D. Zero-complexity Transposition
Input file: standard input
Output file: standard output

You are given a sequence of integer numbers. Zero-complexity transposition
of the sequence is the reverse of this sequence. Your task is to write a
program that prints zero-complexity transposition of the given sequence.

Input
The first line of the input file contains one integer n-length of the
sequence (0 < n ≤ 10 000). The second line contains n integers
numbers-a1, a2, …, an (-1 000 000 000 000 000 ≤ ai ≤ 1 000 000 000 000
000).

Output
On the first line of the output file print the sequence in the reverse
order.

Sample input and output
Standard input                           standard output
3                                        3 2 1
1 2 3

5                                        9 -8 6 4 -3
-3 4 6 -8 9

回復話題
上傳/修改頭像

武漢是哪個省的省會城市(答案為兩個字)?

考研論壇提示:
1、請勿發布個人聯系方式或詢問他人聯系方式,包括QQ和手機等。
2、未經允許不得發布任何資料出售、招生中介等廣告信息。
3、如果發布了涉及以上內容的話題或跟帖,您在考研網的注冊賬戶可能被禁用。

網站介紹 | 關于我們 | 聯系方式 | 廣告業務 | 幫助信息
©1998-2015 ChinaKaoyan.com Network Studio. All Rights Reserved.

中國考研網-聯系地址:上海市郵政信箱088-014號 郵編:200092 Tel & Fax:021 - 5589 1949 滬ICP備12018245號

自拍偷拍亚洲综合_国产福利91精品一区_中文字幕在线亚洲三区_一区二区三区四区五区精品
日韩免费观看高清完整版 | 综合精品久久久| 91麻豆精品国产自产在线观看一区| 日本不卡不码高清免费观看| 亚洲成人av免费| 中文字幕佐山爱一区二区免费| 久久久久国产成人精品亚洲午夜| 欧美日本一区二区在线观看| 久久av在线| 在线一区二区三区四区五区| 国产亚洲一区二区三区在线播放| 国产99久久久国产精品免费看| 欧美日本视频在线| 久久综合狠狠| 欧美在线色视频| 久久精品官网| 国产精品一区二区无线| 全国精品久久少妇| 日日摸夜夜添夜夜添亚洲女人| 图片区小说区国产精品视频| 亚洲综合区在线| 三级精品在线观看| 亚洲h在线观看| 亚洲成在线观看| 日本欧美大码aⅴ在线播放| 视频一区欧美日韩| 日本网站在线观看一区二区三区 | 精品国产精品网麻豆系列| 91精品在线观看入口| 欧美人与禽zozo性伦| 欧美一区二区成人| 精品欧美黑人一区二区三区| 久久久精品欧美丰满| 国产精品二区一区二区aⅴ污介绍| 中国色在线观看另类| 亚洲成人av福利| 久久精品国产色蜜蜜麻豆| 成人理论电影网| 黄色成人在线网址| 亚洲乱亚洲高清| 7777女厕盗摄久久久| 2020国产成人综合网| 亚洲日本乱码在线观看| 亚洲电影欧美电影有声小说| 蜜桃视频一区二区三区 | 在线不卡欧美| 久久久久久穴| 国产性天天综合网| 亚洲综合免费观看高清完整版 | 久久精品国产精品亚洲精品| 国产精品一区在线观看乱码 | 亚洲高清网站| 在线看国产一区| 国产精品久久毛片av大全日韩| 亚洲风情在线资源站| 成人av网站在线| 亚洲黄色一区二区三区| 91精彩视频在线| 国产精品白丝在线| 久久国产精品色婷婷| 在线看片日韩| 欧美日韩免费观看一区二区三区| 欧美丝袜自拍制服另类| 亚洲丝袜自拍清纯另类| 美日韩一区二区| 国产精品videosex极品| av成人激情| 欧美电影免费观看完整版| 亚洲欧美偷拍卡通变态| av中文字幕亚洲| 久久久久久夜| 日韩一区中文字幕| 国产91露脸合集magnet | 国产清纯在线一区二区www| 五月婷婷欧美视频| 国产精品一区二区在线观看网站| 久久国产88| 国产精品水嫩水嫩| 国产一区二区三区四区老人| 色婷婷综合激情| 亚洲欧美一区二区三区久本道91| 国产精品 欧美精品| 国产亚洲二区| 国产欧美大片| 欧美三级日韩在线| 国产精品免费久久| 国产精品系列在线播放| 亚洲欧美日本日韩| 中文字幕免费不卡| av影院午夜一区| 欧美亚洲动漫制服丝袜| 一区二区三区不卡视频在线观看| 成人精品小蝌蚪| 欧美日韩亚洲丝袜制服| 亚洲国产一区视频| 亚洲国产一区二区在线| 久久久久88色偷偷免费| 国产一区二区在线免费观看| 蜜桃久久精品乱码一区二区| 国产精品成人在线观看| 中文字幕一区二区三中文字幕| 国产黄色91视频| 欧美无砖专区一中文字| 午夜私人影院久久久久| 在线亚洲激情| 日韩毛片视频在线看| 91美女片黄在线| 久久伊人蜜桃av一区二区| 国产乱码精品一区二区三| 在线中文字幕不卡| 午夜精品一区二区三区三上悠亚| 天堂一区二区在线| 亚洲一区区二区| 日韩美女啊v在线免费观看| 国产精品hd| 国产精品人成在线观看免费| 91影视在线播放| 国产亚洲午夜高清国产拍精品 | 久久天天做天天爱综合色| 国产日韩欧美一区二区三区乱码 | 好吊一区二区三区| 亚洲国产成人午夜在线一区| 91啪在线观看| 欧美国产乱子伦| 国产中文一区二区| 亚洲丝袜自拍清纯另类| 亚洲精品偷拍| 亚洲va天堂va国产va久| 亚洲人成免费| 亚洲一区二区免费视频| 西西裸体人体做爰大胆久久久| 在线免费亚洲电影| 国产主播一区二区| 欧美一区二区不卡视频| av网站一区二区三区| 久久久99免费| 尹人成人综合网| 日韩精品国产精品| 欧美精品一二三| 激情另类综合| 奇米影视7777精品一区二区| 亚洲二区在线观看| 精品成人免费观看| 欧美午夜精品免费| 日韩伦理免费电影| 黄色另类av| 亚洲精品亚洲人成人网| 日日夜夜免费精品| 成人av第一页| 在线成人高清不卡| 亚洲少妇诱惑| 国产精品一区二区a| 老司机精品视频网站| 4hu四虎永久在线影院成人| 欧美一区二区三区免费在线看 | 26uuu国产日韩综合| 国产一区二区主播在线| 亚洲永久精品大片| 国产精品久久久久久久久免费桃花 | 3d动漫精品啪啪| 美女日韩在线中文字幕| 日韩一级完整毛片| 国产精一品亚洲二区在线视频| 国产亚洲一区二区三区在线观看| 一区二区三区四区五区精品| 国产三级欧美三级日产三级99 | 久久精品欧美一区二区三区不卡 | 久久xxxx| 欧美在线视屏| 国产一区二区精品久久| 一区二区三区蜜桃网| 久久久精品免费免费| 欧美在线观看一二区| 国产日韩高清一区二区三区在线| a级精品国产片在线观看| 久久99精品网久久| 丝袜美腿成人在线| 亚洲乱码日产精品bd| 国产三级欧美三级| 精品久久人人做人人爱| 欧美精品国产精品| 91国偷自产一区二区开放时间| 99一区二区| 最新日韩av| 很黄很黄激情成人| 欧美成人日本| 91麻豆自制传媒国产之光| 国产伦精品一区二区三区免费 | 尤物在线精品| 亚洲午夜精品久久| 欧美色123| 国产精品hd| 欧美日韩综合精品| 国产精品久久久久毛片软件| 2023国产精品| 337p日本欧洲亚洲大胆精品 | 精品一区二区三区影院在线午夜| 五月激情丁香一区二区三区| 亚洲成人在线免费| 色久优优欧美色久优优|